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CloseThe Class 8 is an important year in a student’s life and Maharashtra State Board Maths is one of the subjects that require dedication, hard work, and practice. It’s a subject where you can score well if you are well-versed with the concepts, remember the important formulas and solving methods, and have done an ample amount of practice. Worry not! Home Revise is here to make your Class 8 journey even easier. It’s essential for students to have the right study material and notes to prepare for their board examinations, and through Home Revise, you can cover all the fundamental topics in the subject and the complete Maharashtra State Board Class 8 Maths Book syllabus.
Practice set 3.1 PAGE NO: 15
1. Express the following numbers in index form.
(1) Fifth root of 13
(2) Sixth root of 9
(3) Square root of 256
(4) Cube root of 17
(5) Eighth root of 100
(6) Seventh root of 30
Solution:
In general, nth root of ‘a’ is expressed as a1/n . where, a is the base and 1/5 is the index.
So now,
(1) Fifth root of 13
Index form of fifth root of 13is expressed as 131/5 .
(2) Sixth root of 9
Index form of sixth root of 9 is expressed as 91/6 .
(3) Square root of 256
Index form of square root of 256 is expressed as 2561/2 .
(4) Cube root of 17
Index form of cube root of 17 is expressed as 171/3 .
(5) Eighth root of 100
Index form of eighth root of 100 is expressed as 1001/8 .
(6) Seventh root of 30
Index form of seventh root of 30 is expressed as 301/7 .
2. Write in the form ‘nth
root of a’ in each of the following numbers.
Solution:
In general, a1/n is written as ‘nth root of a’.
So now,
(1) (81)1/4
(81)1/4 is written as ‘4th root of 81’.
(2) (49)1/2
(49)1/2 is written as ‘square root of 49’.
(3) (15)1/5
(15)1/5 is written as ‘5th root of 15’.
(4) (512)1/9
(512)1/9 is written as ‘9th root of 512’.
(5) (100)1/19
(100)1/19 is written as ‘19th root of 100’.
(6) (6)1/7
(6)1/7 is written as ‘7th root of 6’.
Practice set 3.2 PAGE NO: 16
1. Complete the following table.
Sr. No. | Number | Power of the root | Root of the power |
(1) | (225)3/2 | Cube of square root of 225 | Square root of cube of 225 |
(2) | (45)4/5 | ||
(3) | (81)6/7 | ||
(4) | (100)4/10 | ||
(5) | (21)3/7 |
Solution:
Generally we can express the number am/n as
am/n = (am )1/n means ‘nth root of mth power of a’.
am/n = (a1/n )m means ‘mth power of nth root of a’.
So by using the above rules let us fill the table:
Sr. No. | Number | Power of the root | Root of the power |
(1) | (225)3/2 | Cube of square root of 225 | Square root of cube of 225 |
(2) | (45)4/5 | Fourth power of fifth root of 45 | Fifth root of fourth power of 45 |
(3) | (81)6/7 | Sixth power of seventh root of 81 | Seventh root of sixth power of 81 |
(4) | (100)4/10 | Fourth power of tenth root of 100 | Tenth root of fourth power of 100 |
(5) | (21)3/7 | Cube of seventh root of 21 | Seventh root of cube of 21 |
2.
Write the following number in the form of rational indices.
(1) Square root of 5th
power of 121.
(2) Cube of 4th
root of 324.
(3) 5th
root of square of 264.
(4) Cube of cube root of 3.
Solution:
We know that ‘nth root of mth power of a’ is expressed as (am )1/n .
And ‘mth power of nth root of a’ is expressed as (a1/n )m .
So by using the above rules let us find
(1) Square root of 5th power of 121.
Square root of 5th power of 121 is expressed as (1215 )1/2 or (121)5/2 .
(2) Cube of 4th root of 324.
Cube of 4th root of 324 is expressed as (3241/4 )3 or (324)3/4 .
(3) 5th root of square of 264.
5th root of square of 264 is expressed as (2642 )1/5 or (264)2/5 .
(4) Cube of cube root of 3.
Cube of cube root of 3 is expressed as (31/3 )3 or (31)3/3 .
Practice set 3.3 PAGE NO: 18
1. Find the cube root of the following numbers.
(1) 8000
(2) 729
(3) 343
(4) -512
(5) -2744
(6) 32768
Solution:
(1) 8000
Firstly let us find the factor of 8000
8000 = 2 × 2 × 2 × 2 × 2 × 2 × 5 × 5 × 5
So to find the cube root, we pair the prime factors in 3’s.
8000 = (2 × 2 × 5)3
= (2 × 10)3
= 203
Hence, cube root of 8000 = ∛(8000)
= (203 )1/3
= 20
(2) 729
Firstly let us find the factor of 729
729 = 9 × 9 × 9
So to find the cube root, we pair the prime factors in 3’s.
729 = 93
Hence, cube root of 729 = ∛(729)
= (93 )1/3
= 9
(3) 343
Firstly let us find the factor of 343
343 = 7 × 7 × 7
So to find the cube root, we pair the prime factors in 3’s.
343 = 73
Hence, cube root of 343 = ∛(343)
= (73 )1/3
= 7
(4) -512
Firstly let us find the factor of -512
-512 = (-8) × (-8) × (-8)
So to find the cube root, we pair the prime factors in 3’s.
-512 = (-8)3
Hence, cube root of -512 = ∛(-512)
= (-83 )1/3
= -8
(5) -2744
Firstly let us find the factor of -2744
-2744 = (-14) × (-14) × (-14)
So to find the cube root, we pair the prime factors in 3’s.
-2744 = (-14)3
Hence, cube root of -2744 = ∛(-2744)
= (-143 )1/3
= -14
(6) 32768
Firstly let us find the factor of 32768
32768 = 32 × 32 × 32
So to find the cube root, we pair the prime factors in 3’s.
32768 = 323
Hence, cube root of 32768 = ∛(32768)
= (323 )1/3
= 32
2.
Simplify:
Solution:
Cube roots are used in day to day Mathematics, such as in powers and exponents or to find the side of a three-dimensional cube when its volume is given. Here, many such exercise problems are given, students can practice the solutions to secure good marks in the exams.